Admittance Concordance
Admittance
Section titled “Admittance”Concordance status: generated from processed OCR/PDF text. Treat these as source-location aids until each passage is checked against the scan.
481 hits
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10 sources
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79 sections
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Matched Aliases
Section titled “Matched Aliases”admittance, admittances
Source Distribution
Section titled “Source Distribution”| Source | Hits | Sections |
|---|---|---|
| Theory and Calculation of Alternating Current Phenomena | 136 | 17 |
| Theory and Calculation of Alternating Current Phenomena | 109 | 15 |
| Theory and Calculation of Alternating Current Phenomena | 73 | 13 |
| Theory and Calculation of Electric Apparatus | 68 | 9 |
| Theoretical Elements of Electrical Engineering | 55 | 9 |
| Theory and Calculation of Electric Circuits | 16 | 5 |
| Theory and Calculation of Transient Electric Phenomena and Oscillations | 9 | 4 |
| Engineering Mathematics: A Series of Lectures Delivered at Union College | 7 | 3 |
| Elementary Lectures on Electric Discharges, Waves and Impulses, and Other Transients | 4 | 2 |
| Elementary Lectures on Electric Discharges, Waves and Impulses, and Other Transients | 4 | 2 |
Section Hits
Section titled “Section Hits”Representative Source Snippets
Section titled “Representative Source Snippets”Chapter 16: Induction Motor - 28 hit(s)
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... econdary frequency is s N, the secondary in- duced E.M.F. (reduced to primary system) is El = — se. Let I0 = exciting current, or current passing through the motor, per primary circuit, when doing no work (at synchronism), and K= g -j- j 'b = orimary admittance per circuit = — . We thus have, ge = magnetic energy current, ge* = loss of power oy hysteresis (and eddy currents) per primary coil. Hence = total loss of energy by hysteresis and eddys, as calculated according to Chapter X. be = magnetizing cur ...Chapter 20: Single-Phase Induction Motors - 23 hit(s)
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... sity — the total volt-amperes excitation of the single-phase induction motor must be the same as of the same motor on polyphase circuit, it follows that by operating a quarter-phase motor from single-phase circuit on one primary coil, its primary exciting admittance is doubled. Operating a three-phase motor single-phase on one circuit its primary exciting admittance is trebled. The self-inductive primary impedance is the same single-phase as polyphase, but the secondary impedance reduced to the primary is lowered, s ...Apparatus Section 3: Induction Machines: Single -phase Induction Motor - 22 hit(s)
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... admit- tance per circuit Y = g — jb and self-inductive impedances ZQ = rQ + jxQ and Zi = TI + jxi per circuit with the same motor operating as single-phase motor from one pair of termi- nals, the single-phase exciting admittance is Y' = 3 Y (so as to give, the same volt-amperes excitation 3 eF), the primary 330 ELEMENTS OF ELECTRICAL ENGINEERING self-inductive impedance is the same, ZQ = r0 + jxo', the sec- ondary self-inductive impedance si ...Chapter 17: The Alternating-Current Transformer - 21 hit(s)
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... y much smaller. Symbolic Method 149. In symbolic representation by complex quantities the transformer problem appears as follows: The exciting current, /oo, of the transformer depends upon the primary e.m.f., which dependence can be represented by an admittance, the "primary admittance," Fo = g^i — jbo, of the transformer. The resistance and reactance of the primary and the secondary circuit are represented in the impedance by Zo = To + jxo, and Zi = ri + jxi. Within the limited range of variation of the mag ...Chapter 12: Effective Resistance And Reactance - 20 hit(s)
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... z — where z is determined by the magnetic characteristic of the iron and the shape of the magnetic and electric circuits — the impedance is represented, in phase and intensity, by the symbolic expression, Z — r -{- jx =^ z '&\n a -\- jz cos a; and the admittance by, 1 ^ g — JO = - Bin a — J- cos a = y sm a — jy cos a. The quantities z, r, x, and y, g, h are, however, not constants as in the case of the circuit without iron, but depend upon the intensity of magnetization, B — that is, upon the e.m.f. This depen ...Chapter 10: Effective Resistance And Reactance - 18 hit(s)
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... s, — where s is determined by the mag- netic characteristic of the iron, and the shape of the magnetic and electric circuits, — the impedance is repre- sented, in phase and intensity, by the symbolic expression, Z = r — jx = z sin a — jz cos a ; and the admittance by, Y = g + j b = - sin a -j- j - cos a = y sin a -f- jy cos a. z z The quantities, z, r, x, and y, g, b, are, however, not constants as in the case of the circuit without iron, but depend upon the intensity of magnetization, (B, — that is, upon the ...Chapter 8: Admittance, Conductance, Susceptance - 17 hit(s)
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CHAPTER VIII ADMITTANCE, CONDUCTANCE, SUSCEPTANCE 48. If in a continuous-current circuit, a number of resistances, Ti, r2, ?'3, . . ., are connected in series, their joint resistance, R, is the sum of the individual resistances, K = ri + r2 + ra + . . . If, however, a number o ...Chapter 14: The Alternating-Current Transformer - 17 hit(s)
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... PHENOMENA. Symbolic Method. 134. In symbolic representation by complex quantities the transformer problem appears as follows : The exciting current, 700, of the transformer depends upon the primary E.M.F., which dependance can be rep- resented by an admittance, the " primary admittance," °f tne transformer. Fig. 105. The resistance and reactance of the primary and the secondary circuit are represented in the impedance by Z0=r0- jx0, and Zl=rl- j xl . Within the limited range of variation of the magnetic ...Theory Section 17: Impedance and Admittance - 16 hit(s)
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17. IMPEDANCE AND ADMITTANCE 82. In direct-current circuits the most important law is Ohm's law, e -i or e r ir, or r = -.> where e is the e.m.f. impressed upon resistance r to produce current i therein. Since in alternating ...Chapter 10: F - 16 hit(s)
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... — where z is determined by the mag- netic characteristic of the iron, and the shape of the magnetic and electric circuits, — the impedance is repre- sented, in phase and intensity, by the symbolic expression, Z =^ r ^ jx = ;? sin a — jz cos a ; and the admittance by, K = ^ + y ^ = - sin a + y - cos a = >» sin a + jy cos a. z z The quantities, xr, r, ;r, and y^ gy 6, are, however, not constants as in the case of the circuit without iron, but depend upon the intensity of magnetization, (B, — that is, upon the E ...Chapter 5: Single-Phase Induction Motor - 16 hit(s)
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... ll only their component parallel with the primary circuit corres ponds. 61. Hereby the single-phase motor constants are derived from the constants of the same motor structure as polyphase motor. Let, in a polyphase motor: Y = g — jb = primary exciting admittance; 2o = To + Jin = primary self-inductive im- pedance; Z\ = fi + jxi = secondary self-inductive im- pedance (reduced to the pri- mary by the ratio of turns, in the usual manner}; the characteristic constant of the motor then is: & - y (z„ + zx). (i) ...Chapter 7: Admittance, Conductance, Susceftance - 15 hit(s)
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CHAPTER VII. ADMITTANCE, CONDUCTANCE, SUSCEFTANCE. 38. If in a continuous-current circuit, a number of resistances, rj, rj, rg, . . . are connected in series, their joint resistance, Ry is the sum of the individual resistances ^ = ^1 + ^2 + 'a + • • • If, however, a number ...Chapter 13: Ths Alternating^Cnrrent Traxsfobmer - 15 hit(s)
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... T PHENOMKAA Symbolic Method. 124- In symbolic representation by complex quantities the transformer problem appears as follows : The exciting current, /„, of the transformer depends upon the primary K.M.K., which dcpendance can be rc|> resented by an admittance, the " primary admittance," Y^=^ g^ ■\- j b^, of the transformer. rig. 9B. The resistance and reactance of the primary and the secondary circuit are represented in the impedance by ^u = r^ —j^ut and Z| = r, —Jx\- Within the limited range of variatio ...Chapter 7: Admittance, Conductance, Susceptance - 15 hit(s)
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CHAPTER VII. ADMITTANCE, CONDUCTANCE, SUSCEPTANCE. 38. If in a continuous-current circuit, a number of resistances, ?\, r%, r3, . . . are connected in series, their joint resistance, R, is the sum of the individual resistances If, however, a number of resistances are connected ...Chapter 4: Induction Motor With Secondary Excitation - 12 hit(s)
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... or and apparent efficiency necessarily are very low. As illustration is shown in Fig. 20 the load curve of a typical 100-hp. 60-cycle 80-polar induction motor (90 revolutions per minute) of the constants: Impressed voltage: ea = 500. Primary exciting admittance: Ya = 0.02 — 0.6 j. Primary self-inductive impedance: Zu = 0.1 + 0.3j. Secondary self-inductive impedance: Zi = 0.1 + 0.3 j. INDUCTION MOTOR 53 As seen, at full-load of 75 kw. output, the efficiency is 80 per cent., which is fair for a slow-spee ...Chapter 35: Balanced Symmetrical Polyphase Systems - 11 hit(s)
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... tages are usually called in a three-phase systeni, delta voltage c = Y voltage 448 BALANCED SYMMETRICAL POLYPHASE SYSTEMS 449 That is, all ring voltages are divided, all ring currents multiplied with c; all ring impedances are divided, all ring admittances multiplied with the square of the ratio, c^. For instance, if in a three-phase induction motor with delta- connected circuits, the impedance of each circuit is Z = r -{- jx, and the voltage impressed upon the circuit terminals E, and the motor is sup ...Chapter 1: Speed Control Of Induction Motors - 11 hit(s)
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... vary relatively little with the magnetic density and thus the current, over a wide range,1 thus may approxi- mately be assumed as constant. That is, the hysteretic con- ductance is proportional to the susceptance : g' = V tan a. ((>) Thus, the exciting admittance, of a closed magnetic circuit of negligible resistance and negligible eddy-current losses, at the frequency of slip, «, is given by: Y' = g' - jb' = V (tan a - j) = - J = (tan a - j) (7) 8 8 8 1 "Theoiy and Calculation of Al format iri^-rurr^nt Phfj ...Apparatus Section 2: Induction Machines: Polyphase Induction Motor - 9 hit(s)
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... ion machine shall be treated, and the single-phase type discussed only in so far as it differs from the typical polyphase machine. 2. CALCULATION 136. In the polyphase induction motor, Let Y = g — jb = primary exciting admittance, or admit- tance of the primary circuit with open secondary circuit; that is, ge = magnetic power current, be = wattless magnetizing current, where e = counter-generated e.m.f. of the motor; ZQ = r0 + jxQ = primary se ...