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Chapter 31: Three-Phase System

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FieldValue
SourceTheory and Calculation of Alternating Current Phenomena
Year1900
Section IDtheory-calculation-alternating-current-phenomena-1900-chapter-31
Locationlines 25598-25903
Statuscandidate
Word Count528
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CHAPTER XXXI. THREE-PHASE SYSTEM. 292. With equal load of the same phase displacement in all three branches, the symmetrical three-phase system offers no special features over those of three equally loaded single-phase systems, and can be treated as such ; since the mutual reactions between the three phases balance at equal distribution of load, that is, since each phase is acted upon by the preceding phase in an equal but opposite manner as by the following phase. With unequal distribution of load between the different branches, the voltages and phase differences become more or less unequal. These unbalancing effects are obviously maxi- mum, if some of the phases are fully loaded, others unloaded, Let: E — E.M.F. between branches 1 and 2 of a three-phaser. Then: « E = E.M.F. between 2 and 3, (*£=
... se unbalancing effects are obviously maxi- mum, if some of the phases are fully loaded, others unloaded, Let: E — E.M.F. between branches 1 and 2 of a three-phaser. Then: « E = E.M.F. between 2 and 3, (*£= E.M.F. between 3 and 1, where, e= ^1= ~ - Let ZD Z2, Zs = impedances of the lines issuing from genera- tor terminals 1, 2, 3, and Yl} Y2, Ys = admittances of the consumer circuits con- nected between lines 2 and 3, 3 and 1, 1 and 2. Jf then, ID It, /8, are the currents issuing from the generator termi- nals into the lines, it is, /I + ...
CHAPTER XXXI. THREE-PHASE SYSTEM. 292. With equal load of the same phase displacement in all three branches, the symmetrical three-phase system offers no special features over those of three equally loaded single-phase systems, and can be treated as such ; since the mutual reactions between the three phases balance at equal distribution of load, that is, sin ...
... E = E.M.F. between 2 and 3, (*£= E.M.F. between 3 and 1, where, e= ^1= ~ - Let ZD Z2, Zs = impedances of the lines issuing from genera- tor terminals 1, 2, 3, and Yl} Y2, Ys = admittances of the consumer circuits con- nected between lines 2 and 3, 3 and 1, 1 and 2. Jf then, ID It, /8, are the currents issuing from the generator termi- nals into the lines, it is, /I + /2 + /3 = 0. (1) THREE-PHASE SYSTEM. 479 If //, 72', 7/ = currents flowing through the admittances Y1, F2, F3, from 2 to 3, 3 to 1, 1 to 2, it is, /! = /,'-/,', or, / ...
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