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Chapter 37: Quarter-Phase System

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FieldValue
SourceTheory and Calculation of Alternating Current Phenomena
Year1916
Section IDtheory-calculation-alternating-current-phenomena-chapter-37
Locationlines 38393-40115
Statuscandidate
Word Count3709
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CHAPTER XXXVII QUARTER-PHASE SYSTEM 310. In a three- wire quarter-phase system, or quarter-phase system with common return-wire of both phases, let the two outside terminals and wires be denoted by 1 and 2, the middle wire or common return by 0. It is then, El = E = e.m.f. between 0 and 1 in the generator. Ei = jE = e.m.f. between 0 and 2 in the generator. Let 1 1 and 1 2 = currents in 1 and in 2, 7o = current in 0, Z] and Z2 = impedances of lines 1 and 2, Zo = impedance of line 0, Yi and F2 = admittances of circuits 0 to 1, and 0 to 2, /'i and /'2 = currents in circuits 0 to 1, and 0 to 2, E\ and E'2 = potential
... ual generated e.m.f., alternator, 272 Admittance, 55 of dielectric, 154 due to eddy currents, 137 to hysteresis, 129 Admittivity of dielectric circuit, 160 Air-gap in magnetic circuit, 119, 132 Ambiguity of vectors, 39 Amplitude, 6, 20 Apparent capacity of distorted wave, 386 efficiency of induction motor, 234 impedance of transformer, 201 torque efficiency of induction motor, 234 Arc causing harmonics, 353 as pulsating resistance, 352 volt-ampere characteristic, 354 wave constrtiction, 355 Armature reaction of alternator, 260, 27 ...
... terminals and wires be denoted by 1 and 2, the middle wire or common return by 0. It is then, El = E = e.m.f. between 0 and 1 in the generator. Ei = jE = e.m.f. between 0 and 2 in the generator. Let 1 1 and 1 2 = currents in 1 and in 2, 7o = current in 0, Z] and Z2 = impedances of lines 1 and 2, Zo = impedance of line 0, Yi and F2 = admittances of circuits 0 to 1, and 0 to 2, /'i and /'2 = currents in circuits 0 to 1, and 0 to 2, E\ and E'2 = potential differences at circuit 0 to 1, and 0 to 2. it is then, Ii -\- h -\- h = 0, or, lo = — {I ...
... n a three- wire quarter-phase system, or quarter-phase system with common return-wire of both phases, let the two outside terminals and wires be denoted by 1 and 2, the middle wire or common return by 0. It is then, El = E = e.m.f. between 0 and 1 in the generator. Ei = jE = e.m.f. between 0 and 2 in the generator. Let 1 1 and 1 2 = currents in 1 and in 2, 7o = current in 0, Z] and Z2 = impedances of lines 1 and 2, Zo = impedance of line 0, Yi and F2 = admittances of circuits 0 to 1, and 0 to 2, /'i and /'2 = currents in circuits 0 to 1, ...
... (5) Hence, the balanced quarter-phase system with common re- turn is unbalanced with regard to voltage and phase relation, or in other words, even if in a quarter-phase system with common return both branches or phases are loaded equally, with a load of the same phase displacement, nevertheless the system becomes unbalanced, and the two e.m.fs. at the end of the hne are neither equal in magnitude, nor in quadrature with each other. B. One Branch Loaded, One Unloaded Zi = Z2 = Z, Z -^• (a) Fi = 0, F2 = F, {b) Fi = Y, Y, = 0. 464 ALTERNATING-CU ...
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