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General Lectures on Electrical Engineering Formula Map

Review layer: these are OCR/PDF-text formula candidates. Promote only after scan verification, mathematical transcription, and notation review.

134

Formula and equation candidates.

16

Strong formula candidates.

29

Reviewable relation candidates.

FamilyCandidates
General Equation Candidates68
Apparatus, Machines, And Power Systems17
Waves, Lines, Radiation, And Frequency15
Impedance, Reactance, And Admittance14
Power, Energy, Work, And Efficiency13
Symbolic AC And Complex Quantities6
Engineering Mathematics Foundations1
CandidateFamilyOCR/PDF textRoutes
general-lectures-electrical-engineering-eq-candidate-0026
strong-formula-candidate
symbolic-accopper of No. 5, or j of ;j = ^: Cu. = ^source
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general-lectures-electrical-engineering-eq-candidate-0057
strong-formula-candidate
general-equation-candidatesthe resistance, or 10 ohms. The current therefore - = ~r =source
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general-lectures-electrical-engineering-eq-candidate-0071
strong-formula-candidate
waves-radiationIf m == number of phases, the higher harmonics : 2m - isource
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general-lectures-electrical-engineering-eq-candidate-0078
strong-formula-candidate
waves-radiation2g3 QQQ = ^ seconds; the frequency 587 cycles, and if thissource
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general-lectures-electrical-engineering-eq-candidate-0045
strong-formula-candidate
general-equation-candidatesD = .46” ; corona effects begin at the voltage E = 100,000 [)source
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general-lectures-electrical-engineering-eq-candidate-0079
strong-formula-candidate
waves-radiationas for instance, lOO feet = ^230 ~ 52^ miles wave length,source
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general-lectures-electrical-engineering-eq-candidate-0082
strong-formula-candidate
waves-radiationi5ioo + ^ + n^ + Wo = ^ -ond, so giving asource
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general-lectures-electrical-engineering-eq-candidate-0095
strong-formula-candidate
apparatus-systemstion : armature turns m to field turns n = 2 -4- i ; and at thissource
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general-lectures-electrical-engineering-eq-candidate-0097
strong-formula-candidate
apparatus-systemsNo = 2 N, it must be one-half the main field.source
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general-lectures-electrical-engineering-eq-candidate-0098
strong-formula-candidate
apparatus-systemsAt half synchronism, No = 2 ^’ ^^^ transformer field ofsource
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general-lectures-electrical-engineering-eq-candidate-0099
strong-formula-candidate
apparatus-systemsthe commutating field required Fo = 2 F, and the short cir-source
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general-lectures-electrical-engineering-eq-candidate-0102
strong-formula-candidate
apparatus-systemsFo = 2 ^» ^^^ the transformer field thus is four times largersource
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general-lectures-electrical-engineering-eq-candidate-0106
strong-formula-candidate
general-equation-candidates2CI + H2O = CIH + ClOH, that is, hydrochloric + hypo-source
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general-lectures-electrical-engineering-eq-candidate-0128
strong-formula-candidate
general-equation-candidateslength of a discharge of 500,000 cycles is ^qq’qqq = g miles,source
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general-lectures-electrical-engineering-eq-candidate-0042
strong-formula-candidate
general-equation-candidatese = 100,000 R or E = 100,000 D, as the voltage wheresource
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general-lectures-electrical-engineering-eq-candidate-0081
strong-formula-candidate
waves-radiation- ’ - = 25,000. If now somewhere in the middle of thissource
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general-lectures-electrical-engineering-eq-candidate-0039
reviewable-relation-candidate
general-equation-candidates2 d = distance between conductor centres.source
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general-lectures-electrical-engineering-eq-candidate-0047
reviewable-relation-candidate
general-equation-candidatesD= ? =1”source
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general-lectures-electrical-engineering-eq-candidate-0089
reviewable-relation-candidate
general-equation-candidatesconsumed by the brakes is given by the speed E F = 34.5 milessource
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general-lectures-electrical-engineering-eq-candidate-0096
reviewable-relation-candidate
apparatus-systemsNo = 2 N, it must be twice ; at double synchronism :source
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general-lectures-electrical-engineering-eq-candidate-0100
reviewable-relation-candidate
apparatus-systemsAt double synchronism : No = 2 N, the transformer fieldsource
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general-lectures-electrical-engineering-eq-candidate-0022
reviewable-relation-candidate
power-energygives 4 X ; = jg or altogether ^ + ^ = jg of thesource
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general-lectures-electrical-engineering-eq-candidate-0024
reviewable-relation-candidate
power-energyor glof 4 = 24 » ^^’^ so gives a total copper economy ofsource
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general-lectures-electrical-engineering-eq-candidate-0036
reviewable-relation-candidate
general-equation-candidatesat - 7| = 57% of full voltage.source
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general-lectures-electrical-engineering-eq-candidate-0041
reviewable-relation-candidate
general-equation-candidates^ = 100,000source
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general-lectures-electrical-engineering-eq-candidate-0046
reviewable-relation-candidate
general-equation-candidatesD^ = 46,000. ’ ‘source
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general-lectures-electrical-engineering-eq-candidate-0052
reviewable-relation-candidate
general-equation-candidatesV^io* + 1000’ = 1000 and the current in the circuitsource
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general-lectures-electrical-engineering-eq-candidate-0053
reviewable-relation-candidate
general-equation-candidates- = 20 amperes.source
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general-lectures-electrical-engineering-eq-candidate-0056
reviewable-relation-candidate
impedance-admittance1000 - 1000 = o ohms, and the impedance is the same assource
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general-lectures-electrical-engineering-eq-candidate-0076
reviewable-relation-candidate
waves-radiationcircuit is 2 X 80 = 160 miles - conductor and return conductor,source
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