General Lectures on Electrical Engineering Formula Map
Formula Map
Section titled “Formula Map”Review layer: these are OCR/PDF-text formula candidates. Promote only after scan verification, mathematical transcription, and notation review.
134
Formula and equation candidates.
16
Strong formula candidates.
29
Reviewable relation candidates.
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Formula Families
Section titled “Formula Families”Highest-Priority Candidates
Section titled “Highest-Priority Candidates”| Candidate | Family | OCR/PDF text | Routes |
|---|---|---|---|
general-lectures-electrical-engineering-eq-candidate-0026strong-formula-candidate | symbolic-ac | copper of No. 5, or j of ;j = ^: Cu. = ^ | source workbench |
general-lectures-electrical-engineering-eq-candidate-0057strong-formula-candidate | general-equation-candidates | the resistance, or 10 ohms. The current therefore - = ~r = | source workbench |
general-lectures-electrical-engineering-eq-candidate-0071strong-formula-candidate | waves-radiation | If m == number of phases, the higher harmonics : 2m - i | source workbench |
general-lectures-electrical-engineering-eq-candidate-0078strong-formula-candidate | waves-radiation | 2g3 QQQ = ^ seconds; the frequency 587 cycles, and if this | source workbench |
general-lectures-electrical-engineering-eq-candidate-0045strong-formula-candidate | general-equation-candidates | D = .46” ; corona effects begin at the voltage E = 100,000 [) | source workbench |
general-lectures-electrical-engineering-eq-candidate-0079strong-formula-candidate | waves-radiation | as for instance, lOO feet = ^230 ~ 52^ miles wave length, | source workbench |
general-lectures-electrical-engineering-eq-candidate-0082strong-formula-candidate | waves-radiation | i5ioo + ^ + n^ + Wo = ^ -ond, so giving a | source workbench |
general-lectures-electrical-engineering-eq-candidate-0095strong-formula-candidate | apparatus-systems | tion : armature turns m to field turns n = 2 -4- i ; and at this | source workbench |
general-lectures-electrical-engineering-eq-candidate-0097strong-formula-candidate | apparatus-systems | No = 2 N, it must be one-half the main field. | source workbench |
general-lectures-electrical-engineering-eq-candidate-0098strong-formula-candidate | apparatus-systems | At half synchronism, No = 2 ^’ ^^^ transformer field of | source workbench |
general-lectures-electrical-engineering-eq-candidate-0099strong-formula-candidate | apparatus-systems | the commutating field required Fo = 2 F, and the short cir- | source workbench |
general-lectures-electrical-engineering-eq-candidate-0102strong-formula-candidate | apparatus-systems | Fo = 2 ^» ^^^ the transformer field thus is four times larger | source workbench |
general-lectures-electrical-engineering-eq-candidate-0106strong-formula-candidate | general-equation-candidates | 2CI + H2O = CIH + ClOH, that is, hydrochloric + hypo- | source workbench |
general-lectures-electrical-engineering-eq-candidate-0128strong-formula-candidate | general-equation-candidates | length of a discharge of 500,000 cycles is ^qq’qqq = g miles, | source workbench |
general-lectures-electrical-engineering-eq-candidate-0042strong-formula-candidate | general-equation-candidates | e = 100,000 R or E = 100,000 D, as the voltage where | source workbench |
general-lectures-electrical-engineering-eq-candidate-0081strong-formula-candidate | waves-radiation | - ’ - = 25,000. If now somewhere in the middle of this | source workbench |
general-lectures-electrical-engineering-eq-candidate-0039reviewable-relation-candidate | general-equation-candidates | 2 d = distance between conductor centres. | source workbench |
general-lectures-electrical-engineering-eq-candidate-0047reviewable-relation-candidate | general-equation-candidates | D= ? =1” | source workbench |
general-lectures-electrical-engineering-eq-candidate-0089reviewable-relation-candidate | general-equation-candidates | consumed by the brakes is given by the speed E F = 34.5 miles | source workbench |
general-lectures-electrical-engineering-eq-candidate-0096reviewable-relation-candidate | apparatus-systems | No = 2 N, it must be twice ; at double synchronism : | source workbench |
general-lectures-electrical-engineering-eq-candidate-0100reviewable-relation-candidate | apparatus-systems | At double synchronism : No = 2 N, the transformer field | source workbench |
general-lectures-electrical-engineering-eq-candidate-0022reviewable-relation-candidate | power-energy | gives 4 X ; = jg or altogether ^ + ^ = jg of the | source workbench |
general-lectures-electrical-engineering-eq-candidate-0024reviewable-relation-candidate | power-energy | or glof 4 = 24 » ^^’^ so gives a total copper economy of | source workbench |
general-lectures-electrical-engineering-eq-candidate-0036reviewable-relation-candidate | general-equation-candidates | at - 7| = 57% of full voltage. | source workbench |
general-lectures-electrical-engineering-eq-candidate-0041reviewable-relation-candidate | general-equation-candidates | ^ = 100,000 | source workbench |
general-lectures-electrical-engineering-eq-candidate-0046reviewable-relation-candidate | general-equation-candidates | D^ = 46,000. ’ ‘ | source workbench |
general-lectures-electrical-engineering-eq-candidate-0052reviewable-relation-candidate | general-equation-candidates | V^io* + 1000’ = 1000 and the current in the circuit | source workbench |
general-lectures-electrical-engineering-eq-candidate-0053reviewable-relation-candidate | general-equation-candidates | - = 20 amperes. | source workbench |
general-lectures-electrical-engineering-eq-candidate-0056reviewable-relation-candidate | impedance-admittance | 1000 - 1000 = o ohms, and the impedance is the same as | source workbench |
general-lectures-electrical-engineering-eq-candidate-0076reviewable-relation-candidate | waves-radiation | circuit is 2 X 80 = 160 miles - conductor and return conductor, | source workbench |