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Apparatus, Machines, And Power Systems

Routes formulas tied to machines, apparatus, synchronism, and operating power systems.

410

candidate records in this family.

323

reviewable relation candidates.

6

sources represented.

#1Theory and Calculation of Alternating Current PhenomenaChapter 6: Topographic Method- line 3017
E.M.F. of the generator OE°, where Z0 = r0 - jx0 = inter-
#2Investigation of Some Trouble in the Generating System of the Commonwealth Edison Co.Mathematical Appendix 5: Appendix: Synchronous Operation- line 2211
e1 = E cos(…); e2 = E cos(…), OCR candidate
#3Investigation of Some Trouble in the Generating System of the Commonwealth Edison Co.Mathematical Appendix 5: Appendix: Synchronous Operation- line 2212
ei = E cos (0
#4Investigation of Some Trouble in the Generating System of the Commonwealth Edison Co.Mathematical Appendix 5: Appendix: Synchronous Operation- line 2218
e = e1 - e2 = 2E sin(…) sin(…), OCR candidate
#5Investigation of Some Trouble in the Generating System of the Commonwealth Edison Co.Mathematical Appendix 5: Appendix: Synchronous Operation- line 2231
i = (2E / z) sin(…) sin(…), OCR candidate
#6Investigation of Some Trouble in the Generating System of the Commonwealth Edison Co.Mathematical Appendix 5: Appendix: Synchronous Operation- line 2240
z = sqrt(r^2 + x^2); tan a = x / r, OCR candidate
#7Investigation of Some Trouble in the Generating System of the Commonwealth Edison Co.Mathematical Appendix 5: Appendix: Synchronous Operation- line 2397
p’Y=-!|cos(2a>-a)
#8Investigation of Some Trouble in the Generating System of the Commonwealth Edison Co.Mathematical Appendix 5: Appendix: Synchronous Operation- line 2428
P=- sin a sin 2co
#9Investigation of Some Trouble in the Generating System of the Commonwealth Edison Co.Mathematical Appendix 5: Appendix: Synchronous Operation- line 2522
W= ^-sin a (1-cos 2 Wo )
#10Investigation of Some Trouble in the Generating System of the Commonwealth Edison Co.Mathematical Appendix 5: Appendix: Synchronous Operation- line 3483
2Eo sin wo = I (2xx+x)
#11Theory and Calculation of Electric ApparatusChapter 4: Induction Motor With Secondary Excitation- line 6153
” -Pi = U (e0 - ri\ - xi2) + it (xit - n2), (16)
#12Theory and Calculation of Electric ApparatusChapter 4: Induction Motor With Secondary Excitation- line 6157
Pi = cot’i - r (tV + it2)
#13Investigation of Some Trouble in the Generating System of the Commonwealth Edison Co.Mathematical Appendix 5: Appendix: Synchronous Operation- line 2246
tan a = -
#14Investigation of Some Trouble in the Generating System of the Commonwealth Edison Co.Mathematical Appendix 5: Appendix: Synchronous Operation- line 2379
p”i=- cos a
#15Investigation of Some Trouble in the Generating System of the Commonwealth Edison Co.Mathematical Appendix 5: Appendix: Synchronous Operation- line 2385
gives, substituting cos a = -
#16Investigation of Some Trouble in the Generating System of the Commonwealth Edison Co.Mathematical Appendix 5: Appendix: Synchronous Operation- line 2585
CI=E cos (i
#17Investigation of Some Trouble in the Generating System of the Commonwealth Edison Co.Mathematical Appendix 5: Appendix: Synchronous Operation- line 3237
e = 2E sin
#18Investigation of Some Trouble in the Generating System of the Commonwealth Edison Co.Mathematical Appendix 5: Appendix: Synchronous Operation- line 3268
e = 2E sin
#19Investigation of Some Trouble in the Generating System of the Commonwealth Edison Co.Mathematical Appendix 5: Appendix: Synchronous Operation- line 3284
ID=- sin w
#20General Lectures on Electrical EngineeringLecture 14: Alternating Current Railway Motor- line 8744
tion : armature turns m to field turns n = 2 -4- i ; and at this
#21General Lectures on Electrical EngineeringLecture 14: Alternating Current Railway Motor- line 9105
No = 2 N, it must be one-half the main field.
#22General Lectures on Electrical EngineeringLecture 14: Alternating Current Railway Motor- line 9181
At half synchronism, No = 2 ^’ ^^^ transformer field of
#23General Lectures on Electrical EngineeringLecture 14: Alternating Current Railway Motor- line 9183
the commutating field required Fo = 2 F, and the short cir-
#24General Lectures on Electrical EngineeringLecture 14: Alternating Current Railway Motor- line 9190
Fo = 2 ^» ^^^ the transformer field thus is four times larger
#25Investigation of Some Trouble in the Generating System of the Commonwealth Edison Co.Mathematical Appendix 5: Appendix: Synchronous Operation- line 2215
e2 = Ecos (0+co)
#26Investigation of Some Trouble in the Generating System of the Commonwealth Edison Co.Mathematical Appendix 5: Appendix: Synchronous Operation- line 2241
z = r2+x
#27Investigation of Some Trouble in the Generating System of the Commonwealth Edison Co.Mathematical Appendix 5: Appendix: Synchronous Operation- line 2352
: p = a small quantity ; these additional terms in (3) and (4) are
#28Investigation of Some Trouble in the Generating System of the Commonwealth Edison Co.Mathematical Appendix 5: Appendix: Synchronous Operation- line 2440
for a = 0, that is, in the (theoretical)
#29Investigation of Some Trouble in the Generating System of the Commonwealth Edison Co.Mathematical Appendix 5: Appendix: Synchronous Operation- line 2461
- — =- sin a (1
#30Investigation of Some Trouble in the Generating System of the Commonwealth Edison Co.Mathematical Appendix 5: Appendix: Synchronous Operation- line 2545
z= Vr 2+x
#31Investigation of Some Trouble in the Generating System of the Commonwealth Edison Co.Mathematical Appendix 5: Appendix: Synchronous Operation- line 2588
e 2 = E cos (1+s)
#32Investigation of Some Trouble in the Generating System of the Commonwealth Edison Co.Mathematical Appendix 5: Appendix: Synchronous Operation- line 2596
= E<cos (1
#33Investigation of Some Trouble in the Generating System of the Commonwealth Edison Co.Mathematical Appendix 5: Appendix: Synchronous Operation- line 2632
z= Vr 2+x
#34Investigation of Some Trouble in the Generating System of the Commonwealth Edison Co.Mathematical Appendix 5: Appendix: Synchronous Operation- line 3014
- cos (2s0 = a)
#35Investigation of Some Trouble in the Generating System of the Commonwealth Edison Co.Mathematical Appendix 5: Appendix: Synchronous Operation- line 3252
e 2 = E cos (0+w)
#36Investigation of Some Trouble in the Generating System of the Commonwealth Edison Co.Mathematical Appendix 5: Appendix: Synchronous Operation- line 3557
x2 = 2x1 + x, OCR candidate
#37Investigation of Some Trouble in the Generating System of the Commonwealth Edison Co.Mathematical Appendix 5: Appendix: Synchronous Operation- line 3724
Xi = xn+Xi2 = total self inductive reactance of alternators or group
#38Investigation of Some Trouble in the Generating System of the Commonwealth Edison Co.Mathematical Appendix 5: Appendix: Synchronous Operation- line 3728
Xo=xn+x 2
#39Investigation of Some Trouble in the Generating System of the Commonwealth Edison Co.Mathematical Appendix 5: Appendix: Synchronous Operation- line 3998
Xl =.458 +.405 = 863;
#40Investigation of Some Trouble in the Generating System of the Commonwealth Edison Co.Mathematical Appendix 5: Appendix: Synchronous Operation- line 4010
Xl = .318+.347 = .665; M = 67xlO.
#41Investigation of Some Trouble in the Generating System of the Commonwealth Edison Co.Mathematical Appendix 5: Appendix: Synchronous Operation- line 4030
x 2 = 4.95; Xl =.325+.168 = .493; M = 78xl0 6
#42Investigation of Some Trouble in the Generating System of the Commonwealth Edison Co.Mathematical Appendix 5: Appendix: Synchronous Operation- line 4036
Xl = .214+.168 = .382:
#43Investigation of Some Trouble in the Generating System of the Commonwealth Edison Co.Mathematical Appendix 5: Appendix: Synchronous Operation- line 4161
z = .84: 1^ = 78 xlO 6
#44Investigation of Some Trouble in the Generating System of the Commonwealth Edison Co.Mathematical Appendix 5: Appendix: Synchronous Operation- line 4218
z = 1.46: M^SOxlO
#45Theory and Calculation of Alternating Current PhenomenaChapter 5: Symbouc Mbthod- line 2975
the system of ordinary numbers, this definition ofy = V- 1
#46Theory and Calculation of Electric ApparatusChapter 1: Speed Control Of Induction Motors- line 2458
torque curve of the motor with short-circuited secondary, r = 0,
#47Theory and Calculation of Electric ApparatusChapter 2: Multiple Squirrel-Cage Induction Motor- line 3725
E0 = E + Z„f„. (6)
#48Theory and Calculation of Electric ApparatusChapter 2: Multiple Squirrel-Cage Induction Motor- line 3768
as = * (- H h - 1 I
#49Theory and Calculation of Electric ApparatusChapter 2: Multiple Squirrel-Cage Induction Motor- line 3793
ci = - H 1- 6i
#50Theory and Calculation of Electric ApparatusChapter 2: Multiple Squirrel-Cage Induction Motor- line 3804
Eo = Ei{ai + jat + (r0 + jx0) (c, + jc,) }
#51Theory and Calculation of Electric ApparatusChapter 2: Multiple Squirrel-Cage Induction Motor- line 3817
C = -=*=• (17)
#52Theory and Calculation of Electric ApparatusChapter 2: Multiple Squirrel-Cage Induction Motor- line 3819
to = e,\/ci* + c,*. (18)
#53Theory and Calculation of Electric ApparatusChapter 2: Multiple Squirrel-Cage Induction Motor- line 3842
D = D2 + Dh (21)
#54Theory and Calculation of Electric ApparatusChapter 2: Multiple Squirrel-Cage Induction Motor- line 3846
P = (1 - s) Z>. (22)
#55Theory and Calculation of Electric ApparatusChapter 2: Multiple Squirrel-Cage Induction Motor- line 4021
da = a2 + roC2 + XqCi,
#56Theory and Calculation of Electric ApparatusChapter 2: Multiple Squirrel-Cage Induction Motor- line 4032
to = e* Vci2 + cf,
#57Theory and Calculation of Electric ApparatusChapter 2: Multiple Squirrel-Cage Induction Motor- line 4036
P = (1 - s) D,
#58Theory and Calculation of Electric ApparatusChapter 2: Multiple Squirrel-Cage Induction Motor- line 4038
Po = e*1 (cidx + c2d2),
#59Theory and Calculation of Electric ApparatusChapter 2: Multiple Squirrel-Cage Induction Motor- line 4085
/o = U + I* + U + Fo#. (4)
#60Theory and Calculation of Electric ApparatusChapter 2: Multiple Squirrel-Cage Induction Motor- line 4091
tf i = #* + jx, (It + /•), (6)
#61Theory and Calculation of Electric ApparatusChapter 2: Multiple Squirrel-Cage Induction Motor- line 4165
E = Es\ai+ jai + r:’ («. + jo*) + 3 ^ (l + 3 ?) + 3 ?
#62Theory and Calculation of Electric ApparatusChapter 2: Multiple Squirrel-Cage Induction Motor- line 4200
c2 = 62g - 616,
#63Theory and Calculation of Electric ApparatusChapter 2: Multiple Squirrel-Cage Induction Motor- line 4221
a2 = - a2 + ■ - t f2
#64Theory and Calculation of Electric ApparatusChapter 2: Multiple Squirrel-Cage Induction Motor- line 4225
Zo/o = #3 (di + jrf2) (r0 + ix0)
#65Theory and Calculation of Electric ApparatusChapter 2: Multiple Squirrel-Cage Induction Motor- line 4244
#o = #3 (6i + jbt + /i + jf«)
#66Theory and Calculation of Electric ApparatusChapter 2: Multiple Squirrel-Cage Induction Motor- line 4248
(Jz = b2 + /2
#67Theory and Calculation of Electric ApparatusChapter 2: Multiple Squirrel-Cage Induction Motor- line 4284
U = ez Vrfi8 + _dS, (25)
#68Theory and Calculation of Electric ApparatusChapter 2: Multiple Squirrel-Cage Induction Motor- line 4305
D = D, + D2 + D3, (31)
#69Theory and Calculation of Electric ApparatusChapter 2: Multiple Squirrel-Cage Induction Motor- line 4309
P = (1 - s) Z>, (32)
#70Theory and Calculation of Electric ApparatusChapter 2: Multiple Squirrel-Cage Induction Motor- line 4319
Q = «oio. (34)
#71Theory and Calculation of Electric ApparatusChapter 2: Multiple Squirrel-Cage Induction Motor- line 4582
to = ez y/dx2 + dsS
#72Theory and Calculation of Electric ApparatusChapter 2: Multiple Squirrel-Cage Induction Motor- line 4603
D = !>! + D2 + /)3,