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Chapter 18: Surging Of Synchronous Motors

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FieldValue
SourceTheory and Calculation of Electric Apparatus
Year1917
Section IDtheory-calculation-electric-apparatus-chapter-16
Locationlines 20975-21712
Statuscandidate
Word Count2889
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CHAPTER XVIII SURGING OF SYNCHRONOUS MOTORS 166. In the theory of the synchronous motor the assumption is made that the mechanical output of the motor equals the power developed by it. This is the case only if the motor runs at constant speed. If, however, it accelerates, the power input is greater; if it decelerates, less than the power output, by the power stored in and returned by the momentum. Obviously, the motor can neither constantly accelerate nor decelerate, without breaking out of synchronism. If, for instance, at a certain moment the power prod wed by the motor exceeds the mechanical load (as in the moment of throwing off a part of the load), the excess power is consumed by the momentum as acceleration, causing an increase of speed. The result thereof is that the
... is manner a periodic variation of the phase relation between e and to, and correspond- ing variation of speed and current occurs, of an amplitude and period depending upon the circuit conditions and the mechanical momentum. If the amplitude of this pulsation has a positive decrement, that is, is decreasing, the motor assumes after a while a constant position of e regarding ea, that is, its speed becomes uniform. If, however, the decrement of Hie pulsation is negative, an infinitely small pulsation will continuously increase in amplitude, until the moto ...
... onditions of oscillation, and a period, which for small oscillations gives the frequency of oscillation: f „f _ //ee0 sin (a - 0) As instance, let: <?o = 2200 volts. Z = 1 + 4 j ohms, or, z = 4.12; a = 76°. And let the machine, a 16-polar, 60-cycle, 400-kw., revolving- field, synchronous motor, have the radius of gyration of 20 in., a weight of the revolving part of 6000 lb. The momentum then is Af„ = 850,000 joules. Deriving the angles, 0, corresponding to given values of output. P, and excitation, r, from the polar diagram, or from the symbo ...
... ulsation of the synchronous motor occurs, resulting in a change of the phase relation, 0, between the counter e.m.f., e, and the impressed e.m.f., e0 (the latter being of constant fre- quency, thus constant phase), by an angle, 5, where 8 is a periodic function of time, of a frequency very low compared with the impressed frequency, then the phase angle of the counter e.rn.f., e, is P + 6; and the counter e.m.f. is: E = e {cos (0 + 6) - j sin (p + 6)1, 19 290 ELECTRICAL APPARATUS hence the current: / = - {[e0 cos a — e cos (a + 0 + 5)] z — j [ ...
... scilla- tion of slip, in solid field poles, etc., a torque is produced more or less proportional to the deviation of speed from synchronism. This power assumes the form, Pi = c2s, where c is a function of the conductivity of the eddy-current circuit and the intensity of the magnetic field of the machine, c2 is the power which would be required to drive the magnetic field of the motor through the circuits of the anti-surging device at full frequency, if the same relative proportions could be retained at full fre- quency as at the frequency of slip, s. Th ...
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