CHAPTER V. SYMBOUC MBTHOD. 23. The graphical method of representing alternating- current phenomena by polar coordinates of time affords the best means for deriving a clear insight into the mutual rela- tion of the different alternating sine waves entering into the problem. For numerical calculation, however, the graphical method is frequently not well suited, owing to the widely •different magnitudes of the alternating sine waves repre- sented in the same diagram, which make an exact diagram- matic determination impossible. For instance, in the trans- former diagrams (cf. Figs. 18-20), the different magnitudes •will have numerical values in practice, somewhat like E-^ = 100 volts, and /j = 75 amperes, for a non-inductive secon- dary load, as of incandescent lamps. Thus the only reac- tance of the secondary circuit is that of the secondary coil, or, x\ = .08 ohms, giving a lag of eSj = 3.6^. We have also, fty = 30 turns. Uf, = 300 turns. (Fi = 2250 ampere-turns. $f = 100 ampere- turns. Er = 10 volts. £^ = 60 volts. Ei = 1000 volts. The corresponding diagram is shown in Fig. 21. Obvi* ously, no exact numerical values can be taken from a par- allelogram as flat as OF^FF^,, and from the combination of vectors of the relative magnitudes 1 : 6 :100. Hence the importance of the graphical method consists 84 ALTERNATING-CURRENT PHENOMENA. [§§24,25 not SO much in its usefulness for practical calculation, as to aid in the simple understanding of the phenomena involved. 24. Sometimes we can calculate the numerical values trigonometrically by means of the diagram. Usually, how- ever, this becomes too complicated, as will be seen by trying f/g. 27. to calculate, from the above transformer diagram, the ratio of transformation. The primary M.M.F. is given by the equation : — ' $Fo = V^H^i' + 2 IFSFi sin Wi , an expression not well suited as a starting-point for further calculation. A method is therefore desirable which combines the exactness of analytical calculation with the clearness of the graphical representation. Flq, 22. 25. We have seen that the alternating sine wave is represented in intensity, as well as phase, by a vector. Of, which is determined analytically by two numerical quanti- ties — the length, Of, or intensity ; and the amplitude, AO/, or phase is the horizontal component, ^ = /sin 0) is the vertical component of the sine wave. This representation of the sine wave by its rectangular components is very convenient, in so far as it avoids the use of trigonometric functions in the combination or reso- lution of sine waves. Since the rectangular components a and b are the hori- zontal and the vertical projections of the vector represent- ing the sine wave, and the projection of the diagonal of a parallelogram is equal to the sum of the projections of its sides, the combination of sine waves by the parallelogram Fig, 23. law is reduced to the addition, or subtraction, of their rectangular components. That is, Sifie waves arc combined^ or resolved^ by adding^ or subtractings their rectangular components. For instance, if a and b are the rectangular components of a sine wave, /, and d and b* the components of another sine wave, /' (Fig. 23), their resultant sine wave, /^, has the rectangular components a^ == (a •\- d), and b^^(p •\- b'). To get from the rectangular components, a and b, of a sine wave, its total intensity, /, and phase, ; hence the wave a -^jh can also be expressed by — I (cos CO +y sin w), or, by substituting for cos w and sin ^ their exponential expressions, we obtain — Since we have seen that sine waves may be combined or resolved by adding or subtracting their rectangular com- ponents, consequently : — Sine ivavcs may be combined or 7rsolved by adding or subtracting their complex algebraic expressions. For instance, the sine waves, — a +jb and combined give the sine wave — I^{a + a')+j{b + b'). It will thus be seen that the combination of sine waves is reduced to the elementary algebra of complex quantities. 29. If /= / +ji' is a sine wave of alternating current, and r is the resistance, the E.M.F. consumed by the re- sistance is in phase with the current, and equal to the prod- uct of the current and resistance. Or — r/= ri '\' jri\ If L is the inductance, and j: = 2 tt NL the reactance, the E.M.F. produced by the reactance, or the counter §20] SYMBOLIC METHOD. 39' E.M.F. of self-inductance, is the product of the current and reactance, and lags 90° behind the current; it is, therefore, represented by the expression — jxl =jxi — xi\ The E.M.F. required to overcome the reactance is con- sequently 90° ahead of the current (or, as usually expressed, the current lags 90° behind the E.M.F.), and represented by the expression — — ylr/= — Jxi + xi\ Hence, the E.M.F. required to overcome the resistance,, r, and the reactance, jr, is — (r~»/; that is — Z = r —jx is the expression of the impedance of the cir- cuity in complex quantities. Hence, li I = i +ji' is the current, the E.M.F. required to overcome the impedance, Z = r — jxy is — hence, since y^ = — 1 £ = (ri -|- xi') + J (ri' — xi) ; or, if ^ = ^ +je' is the impressed E.M.F., and Z = r —jx the impedance, the current flowing through the circuit is : — Z r — jx or, multiplying numerator and denominator by (r+jx) to eliminate the imaginary from the denominator, we have — 7 ^ (^+J^(^+Jx) ^ er — /x , . /r + )» + (/ - ixy, tan a<, = 7q-^ ; values which easily permit calculation. §33] TOPOGRAPinC METHOD, 43