D. C. COMMUTATING MACHINES 201 is, in the armature during commutation an e.m.f. is generated by its rotation through a magnetic field. This magnetic field may be the magnetic field of armature reaction, or the reverse magnetic field of a commutating pole, or the fringe of the main field of the machine, into which the brushes are shifted. In this case the commutation depends upon the inductance and the resistance of the armature coil and the e.m.f. generated therein by the main magnetic field, and if this magnetic field is a corn- mutating field, is called voltage commutation. In either case the resistance of the brushes and their contact may either be negligible, as usually the case with copper brushes, or it may be of the same or a higher magnitude than the internal resistance of the armature coil A. The latter is usually the case with carbon or graphite brushes. In the former case the resistance of the short-circuit of arma- ture coil A under commutation is approximately constant; in the latter case it varies from infinity in the moment of beginning commutation down to minimum, and then up again to infinity at the end of commutation. 65. (a) Negligible resistance of brush and brush contact. This is more or less approximately the case with copper brushes. Let iQ = current, L = inductance, r — resistance of armature coil, to = -£• = time of commutation, and — e = e.m.f. generated in the armature coil by its rotation through the magnetic field, where e is negative for the magnetic field of armature reaction and positive for the commutating field. Denoting the current in the coil A at time t after beginning of commutation by i, the e.m.f. of self-inductance is _ di Thus the total e.m.f. acting in coil A, di — e -\- ei = — e — L -77* at and the current is e Ldi r r dt 202 ELEMENTS OF ELECTRICAL ENGINEERING Transposing, this expression becomes rdt di the integral of which is - j- = loge (^ + i) - loge c, where loge c = integration constant. Since at t = 0, i = io, we have loge c = log + i0 , therefore (g \ In - + i,J , and ^ = (- + and, at the end of commutation, or, t = to, For perfect commutation, that is, the current at the end of commutation must have reversed and reached its full value in opposite direction. Substituting in this last equation the value i\ from the pre- ceding equation, and transforming, we have taking the logarithms of both terms, L o -t-> and, solving the exponential equation for e, we obtain