D. C. COMMUTATING MACHINES 179 acting upon the air gap between armature and field pole, la = length of air gap, from iron to iron, the density under the magnet pole, that is, in the range BC of Fig. 90, is At a point having the distance lx from the end of the field pole on the armature surface, the distance from the next field pole is ld = Vk2 + lx2, and the density thus, approximately, B C FIG. 92. — Distribution of mganetic flux under a single pole. Herefrom the distribution of magnetic flux is calculated and plotted in Fig. 92, for a single pole BC, along the armature sur- face A, for the length of air gap la = 1, and such a m.m.f. as to L FIG. 93. — Distribution of magnetic force and flux at no load. give Bo = 8000 under the field pole; that is, for /0 = 6400 or HQ = 8000. Around the surface of the direct-current machine armature, alternate poles follow each other. Thus the m.m.f. is constant only under each field pole, but decreases in the space between the field poles, from C to E in Fig. 93, from full value at C to full value in opposite direction at E. The point D midway 180 ELEMENTS OF ELECTRICAL ENGINEERING between C and E} at which the m.m.f. of the field equals zero, is called the "neutral." The distribution of m.m.f. of field excitation is thus given by the line F in Fig. 91. The distribu- tion of magnetic flux as shown in Fig. 91 by BQ is derived by the formula 4irF B 10 I where This distribution of magnetic flux applies only to the no-load condition. Under load, that is, if the armature carries current, the distribution of flux is changed by the m.m.f. of the armature current, or armature reaction. J FIG. 94. — Distribution of flux with current in the armature. 44. Assuming the brushes set at the middle points between adjacent poles, D and G, Fig. 94, the m.m.f. of the armature is maximum at the point connected with the commutator brushes, in this case at the points D and G} and gradually decreases from full value at D to equal but opposite value at G, as shown by the line -Fa in Fig. 94, while the line FQ gives the field m.m.f. or impressed m.m.f. If n = number of turns in series between brushes per pole, i = current per turn, the armature reaction is Fa = ni ampere- turns. Adding Fa and F0 gives the resultant m.m.f. F, and there- from the magnetic distribution: B = The latter is shown as line 10 ld in Fig. 94.