4. POWER AND EFFECTIVE VALUES 20. The power of the continuous e.m.f. E producing con- tinuous current / is P = El. The e.m.f. consumed by resistance r is EI = 7r, thus the power consumed by resistance r is P = 72r. Either EI = E, then, the total power in the circuit is con- sumed by the resistance, or EI < E} then only a part of the power is consumed by the resistance, the remainder by some counter e.m.f., E — EI. If an alternating current i = I0 sin 6 passes through a resist- ance r, the power consumed by the resistance is, i*r = 702r sin2 0 = ^r C1 ~ cos 2 0), & thus varies with twice the frequency of the current, between zero and 70V. The average power consumed by resistance r is, avg. since avg. (cos) = 0. 16 ELEMENTS OF ELECTRICAL ENGINEERING Thus the alternating current i = IQ since 0 consumes in a resist- ance r the same effect as a continuous current of intensity The value / = —7= is called the effective value of the alter- V2 nating current i = IQ sin 0; since it gives the same effect. ET Analogously E = —i is the effective value of the alternating V2 e.m.f., e = EQ sin 6. Since E0 = 2 irfn$, it follows that J' ; = 4.44 fn& ; is the effective alternating e.m.f. generated in a coil of turns n rotating at a frequency of / (in hundreds of cycles per second) through a magnetic field of megalines of force. This is the formula of the alternating-current generator. 21. The formula of the direct-current generator, E = holds even if the e.m.fs. generated in the individual turns are not sine waves, since it is the average generated e.m.f. The formula of the alternating-current generator, E = V2 *fn$, does not hold if the waves are not sine waves, since the ratios of average to maximum and of maximum to effective e.m.f. are changed. If the variation of magnetic flux is not sinusoidal, the effective generated alternating e.m.f. is, E = 7 \/2 7 is called the form factor of the wave, and depends upon its shape, that is, the distribution of the magnetic flux in the magnetic field. Frequently form factor is defined as the ratio of the effect- ive to the average value. This definition is undesirable since it gives for the sine wave, which is always considered the standard wave, a value differing from one. POWER AND EFFECTIVE VALUES 17 EXAMPLES 22. (1) In a star-connected 20-pole three-phase machine, re- volving at 33.3 cycles or 200 rev. per min., the magnetic flux per pole is 6.4 megalines. The armature contains one slot per pole and phase, and each slot contains 36 conductors. All these conductors are connected in series. What is the effective e.m.f. per circuit, and what the effective e.m.f. between the terminals of the machine? Twenty slots of 36 conductors give 720 conductors, or 360 turns in series. Thus the effective e.m.f. is,. = 4.44 X 0.333 X 360 X 6.4 = 3400 volts per circuit. The e.m.f. between the terminals of a star-connected three- phase machine is the resultant of the e.m.fs. of the two phases, which differ by 60 degrees, and is thus 2 sin 60° = -\/3 times that of one phase, thus, E = = 5900 volts effective. 23. (2) The conductor of the machine has a section of 0.22 sq. cm. and a mean length of 240 cm. per turn. At a resistivity (resistance per unit section and unit length) of copper of p = 1.8 X 10~6, what is the e.m.f. consumed in the machine by the resistance, and what the power consumed at 450 kw. output? 450 kw. output is 150,000 watts per phase or circuit, thus 150 000 the current / = omn = 44.2 amperes effective. The resistance of 360 turns of 240 cm. length, 0.22 sq. cm. section and 1.8 X 10~6 resistivity, is 360 X 240 X 1.8 X 10~6 r = - — -rT^ — " = 0.71 ohms per circuit. 44.2 amp. X 0.71 ohms gives 31.5 volts per circuit and (44.2)2 X 0.71 = 1400 watts per circuit, or a total of 3 X 1400 = 4200 watts loss. 24. (3) What is the self-inductance per wire of a three- phase line of 14 miles length consisting of three wires No. 0 (Id = 0.82 cm.), 45 cm. apart, transmitting the output of this 450 kw. 5900- volt three-phase machine? 18 ELEMENTS OF ELECTRICAL ENGINEERING 450 kw. at 5900 volts gives 44.2 amp. per line. 44.2 amp. effective gives 44.2\/2 = 62.5 amp. maximum. 14 miles = 22,400 m. The magnetic flux produced by / amperes in 1000 m. of a transmission line of 2 wires 45 cm. apart and 0.82 cm. diameter was found in paragraph 1, example 3, as 2 $ = 0.188 X 106/, or $ = 0.094 X 106/ for each wire. Thus at 22,300 m. and 62.5 amp. maximum, the flux per wire is $ = 22.3 X 62.5 X 0.094 X 106 = 131 megalines. Hence the generated e.m.f., effective value, at 33.3 cycles is, E = A/2 */ $ = 4.44 X 0.333 X 131 = 193 volts per line; the maximum value is, #o = E X \/2 = 273 volts per line; and the instantaneous value, e = E0 sin (0 - 0i) = 273 sin (0 - 0i) ; or, since 0 = 2 irft = 210 t we have, e = 273 sin 210 (t - h). 25. (4) What is the form factor (a) of the e.m.f. gene- rated in a single conductor of a direct-current machine hav- ing 80 per cent, pole arc and negligible spread of the mag- netic flux at the pole corners, and (6) what is the form fac- tor of the voltage between two collector rings connected to diametrical points of the arm- ature of such a machine? (a) In a conductor during the motion from position A, T? *, T^- shown in Fig. 7, to position FIG. 7. — Diagram of bipolar generator. 15, no e.m.f. is generated; from position B to C a constant e.m.f. e is generated, from C to E again no e.m.f., from E to F a constant e.m.f. — e, POWER AND EFFECTIVE VALUES 19 and from F to A again zero e.m.f. The e.m.f. wave thus is as shown in Fig. 8. The average e.m.f. is ei = 0.8 e; hence, with this average e.m.f., if it were a sine wave, the maxi- mum e.m.f. would be ez = | ei = 0.4 ire, and the effective e.m.f. would be C D FIG. 8. — E.m.f. of a single conductor, direct-current machine 80 per cent, pole arc. The actual square of the e.m.f. is e2 for 80 per cent, and zero for 20 per cent, of the period, and the average or mean square thus is 0.8 e2, and therefore the actual effective value, The form factor 7, or the ratio of the actual effective value e4 to the effective value e3 of a sine wave of the same mean value and thus the same magnetic flux, then is e4 VT6 T = e3 = ^T = 1.006; that is, practically unity. (6) While the collector leads a, b move from the position F, C, as shown in Fig. 6, to B, E, constant voltage E exists between them, the conductors which leave the field at C being replaced 20 ELEMENTS OF ELECTRICAL ENGINEERING by the conductors entering the field at B. During the motion of the leads a, b from B, E to C, F, the voltage steadily decreases, reverses, and rises again, to — E, as the conductors entering the field at E have an e.m.f. opposite to that of the conductors leaving at C. Thus the voltage wave is, as shown by Fig. 9, triangular, with the top cut off for 20 per cent, of the half wave. FIG. 9. — E.m.f. between two collector rings connected to diametrical points of the armature of a bipolar machine having 80 per cent, pole arc. Then the average e.m.f. is e1 = 0.2 E + 2 X = 0.6 E. The maximum value of a sine wave of this average value is e2 = 2 ei — 0-3 irE, and the effective value corresponding thereto is e-2 0.3 irE 63 = 7= V2 The actual voltage square is E2 for 20 per cent, of the time, and rising on a parabolic curve from 0 to E2 during 40 per cent, of the time, as shown in dotted lines in Fig. 9. The area of a parabolic curve is width times one-third of height, or OAE2 hence, the mean square of voltage is 0 and the actual effective voltage is _,4 1/280 ~ e, ~ TT V 27 L°25' SELF-INDUCTANCE AND MUTUAL INDUCTANCE 21 hence, the form factor is 7 r or, 2.5 per cent, higher than with a sine wave.